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In this part, we will apply the Fourier transform to understand time evolution of temperature in an infinite rod. For simplicity, we are assuming that the thermal diffusivity constant a is 1. In this problem there is no boundary, thus no boundary conditions -- just the one-dimensional heat equation and an initial temperature distribution f.
We assume that f is absolutely integrable. In fact, our first initial temperature distribution is graphed below
Suppose u(x,t) is the solution of this problem. Let U(w,t) be the Fourier transform of u with respect to x, i.e., for each t, we take the Fourier transform of the function of x obtained by holding t fixed and letting x vary. In particular, we have
where F is the Fourier transform of the initial temperature distribution function f.
We want to take the Fourier transform of the heat equation to obtain a corresponding condition on U. For t greater than 0, u(x,t) is continuous in x, so we know that the transform of a derivative may be obtained by multiplying the transform of the original function by iw. Thus, the Fourier transform of the second partial of u with respect to x is
Also, since we are taking the Fourier transform with respect to x, the transform of the partial of u with respect to t, may be shown to be just the partial of U with respect to t. So, after we transform, the problem becomes
For each fixed w, this is just a simple first-order initial value problem in t.
In particular, explain where the factor F(w) comes from.
where a and b have the values just determined.
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