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For each of the following systems, determine the number of solutions to the system.
2x1 + 4x2 = 6
3x1 + 6x2 + 2x3 = 7
2x1 + 4x2 + 2x3 = 4
-2x1 - 4x2 + x3 = -7
2x1 + 4x2 = 6
3x1 + 6x2 + 2x3 = 7
2x1 + 4x2 + 2x3 = 4
x1 - 2x2 = 5
2x1 + 4x2 = 6
3x1 + 6x2 + 2x3 = 7
2x1 + 4x2 + 2x3 = 4
2x1 + 5x2 = 8
2x1 + 4x2 = 6
3x1 + 6x2 + 2x3 = 7
2x1 + 4x2 + 2x3 = 4
x1 + 2x2 + 3x3 = 3
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